**Q) Can the number (15 ^{n}), n being a natural number, end with the digit 0 ?**

**Ans: **

For any number to end with the digit 0, it will be divisible by 10

Since 10 = 2 x 5, therefore, a number ending with digit 0 will be divisible by 2 and 5 both.

Next, since factors of 15 are 3 and 5

Hence, for each value of n, 15^{n} will be divisible by 3 and 5, but not by 2.

Therefore, 15^{n} cannot end with the digit 0 for any natural number n.

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