Q) If cot θ =7/8, then find the value of (1+sin θ)(1−sin θ)/(1+cos θ)(1−cos θ).
(Q 22 B – 30/1/3 – CBSE 2026 Question Paper)
Ans:
Step 1: Let’s first simiplify the given expression:
![]()
=
………… (i)
Step 2: From Trigonometric identity, we know that
sin 2 θ + cos 2 θ = 1
∴ 1 – sin 2 θ = cos 2 θ ………… (ii)
and 1 – cos 2 θ = sin 2 θ ………… (iii)
Step 3: Substituting the values from equation (ii) and (iii), we get:
![]()
= ![]()
= cot 2 θ
Step 4: ∵ We are given that cot θ = 7/8
∴ cot 2 θ = (cot θ) 2 = ![]()
Therefore, the value of given expression is
.
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