In the given figure, Δ AHK ~ Δ ABC. If AK = 10cm, BC = 3.5cm

Q) In the given figure, Δ AHK ~ Δ ABC. If AK = 10cm, BC = 3.5cm and HK = 7cm, find the length of AC.

(Q 21 A – 30/2/2 – CBSE 2026 Question Paper)

Ans:

Step 1: Since, it is given that, Δ AHK ~ Δ ABC

∴ $\frac{AK}{HK} = \frac{AC}{BC}$

Step 2: After substituting given values, we get:

∵ AK = 10 cm, HK = 7 cm, BC = 3.5 cm

∴ $\frac{10}{7} = \frac{AC}{3.5}$

∴ AC = $\frac{10 \times 3.5}{7}$

= $\frac{35}{7}$ = 5 cm

Therefore, the length of AC is 5 cm.

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