Q) Find the HCF of 506 and 1155.
Ans:
By prime factorisation, we get:
506 = 2 x 11 x 23
1155 = 3 x 5 x 7 x 11
Since HCF is all the factors between the two numbers and here 11 is the only factor between the two numbers
∴ HCF = 11
Q) Find the HCF of 506 and 1155.
Ans:
By prime factorisation, we get:
506 = 2 x 11 x 23
1155 = 3 x 5 x 7 x 11
Since HCF is all the factors between the two numbers and here 11 is the only factor between the two numbers
∴ HCF = 11