Q) Solve the following pair of linear equations:

152x – 378y = – 74
– 378 x + 152y = – 604

Ans: 

Given the equations:

Solve the following pair of linear equations:
152 x – 378 y = – 74 ….. (i)
– 378 x + 152 y = – 604 ….. (ii)

We need to first simplify the coefficients of variables x and y:

Step 1: Let’s add equation (i) and equation (ii) and we get:

(152 x - 378 y)  + ( - 378 x + 152 y)  = (- 74) + (- 604)

\therefore (152 x - 378 x)  + ( - 378 y + 152 y)  = (- 74) + (- 604)

\therefore - 226 x - 226 y = - 678

\therefore x + y = \frac{- 678}{- 226}

\therefore x + y = 3 ……. (iii)

Step 2: Let’s subtract equation (ii) from equation (i) and we get:

(152 x - 378 y)  - ( - 378 x + 152 y)  = (- 74) - (- 604)

\therefore (152 x + 378 x)  + ( - 378 y - 152 y)  = (- 74 + 604)

\therefore 530 x - 530 y = - 530

\therefore x - y = \frac{- 530}{- 530}

\therefore x - y = 1 ……. (iv)

Step 3: Let’s add the equations (iii) and (iv) and we get:

(x + y) + ( x - y) = (3) + (1)

\therefore 2 x = 4

\therefore x = 2

Step 4: Let’s substitute x = 1, in equation (iii), we get:

(2) + y = 3

\therefore y = 3 - 2

\therefore y = 1

Therefore, x = 2~and~y = 1

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