**Q) **With vertices A, B and C of Δ ABC as centres, arcs are drawn with radii 14 cm and the three portions of the triangle so obtained are removed. Find the total area removed from the triangle.

**Ans: **

We know that the area made by an arc of θ angle is given by = r^{2 }

Therefore total area removed by 3 arcs at 3 vertices:

= r^{2 }+ r^{2 }+ r^{2 }

= r^{2}

Since sum of all angles of a triangle is 180^{0}, therefore ∠ A + ∠ B + ∠ C = 180

Hence, total area removed by 3 arcs at 3 vertices = r^{2}

= (14)^{2}

= 308 cm^{2}

**Therefore, the area removed from triangle is 308 cm ^{2}.**