Q) With vertices A, B and C of Δ ABC as centres, arcs are drawn with radii 14 cm and the three portions of the triangle so obtained are removed. Find the total area removed from the triangle.

Ans:

We know that the area made by an arc of θ angle is given by = r²

Therefore total area removed by 3 arcs at 3 vertices:

= r²   + r²  + r² 

= r²

Since sum of all angles of a triangle is 180⁰, therefore ∠ A + ∠ B + ∠ C = 180

Hence, total area removed by 3 arcs at 3 vertices = r²

= (14)²

= 308 cm²

Therefore, the area removed from triangle is 308 cm².