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Q) Find the value of X if 2 cosec2 300 +  X sin2 600 – (3\4) tan2 300 = 10

Ans:

Given that, 2 \csc^2 30 + X \sin^260 - \frac{3}{4} \tan^230 = 10

2 (2)^2 + X (\frac{\sqrt3}{2})^2 - (\frac{3}{4}) (\frac{1}{\sqrt3})^2 = 10

X (\frac{3}{4}) - (\frac{3}{4}) (\frac{1}{3}) = 2

X (\frac{3}{4}) - \frac{1}{4} = 2

X (\frac{3}{4}) = 2 + \frac{1}{4} = \frac{9}{4}

X = 3

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