Q) Evaluate 2sec2 θ + 3 cosec2 θ – 2 sin θ cos θ if θ = 450.

Ans: Since θ = 450, sec 450 = √2, cosec 450 = √2, sin 450 = \frac{1}{\sqrt2}; cos 450 = \frac{1}{\sqrt2}

2sec2 θ + 3 cosec2 θ – 2 sin θ cos θ

= 2 (√2)2  + 3 (√2)2 – 2 (\frac{1}{\sqrt2}) (\frac{1}{\sqrt2})

= 4 + 6 – 1 = 9

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top