Q) Find the ratio in which the point (8/5, y) divides the line segment joining the points (1, 2) and (2, 3). Also, find the value of y.

ns: Let’s make a diagram for the given question:

Find the ratio in which the point (8/5, y) divides the line segment joining the points (1, 2) and (2, 3). Also, find the value of y.

Let’s consider the point C(8/5, y) divides the line AB in ratio of P : 1

Now, by section formula, coordinates of point P (X, Y) which lies between two points (x1, y1), (x2, y2) will be given by:

P (X,Y) = (\frac{m_1 \times_2 + m_2 \times_1}{m_1 + m_2}, \frac{m_1 Y_2 + m_2 Y_1}{m_1 + m_2})

here, point divides the line in ratio of m1 : m2

Let’s transfer values in the above formula, we get:

For x coordinate:

\frac{8}{5} = \frac{P \times 2 + 1 \times 1}{P + 1}

∴ 8 (P + 1) = 5 (2 P + 1)

∴ 8 P + 8 = 10 P + 5

∴ 8 – 5 = 10 P – 8 P

∴ 3 = 2 P

∴ P = \frac{3}{2}

∴ P : 1 = 3 : 2

Therefore, the point C divides the line AB in ratio of 3:2.

Similarly, for y coordinate:

y = \frac{P \times 3 + 1 \times 2}{P + 1}

= \frac{3 P + 2}{P + 1}

By substituting value of P = \frac{3}{2}, we get:

y = \frac{3 (\frac{3}{2}) + 2}{(\frac{3}{2}) + 1}  = \frac{(\frac{9}{2}) + 2}{(\frac{3}{2}) + 1} = \frac{(\frac{13}{2})}{(\frac{5}{2})} = \frac{13}{5}

Therefore, value of y is \frac{13}{5}.

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