Q) In which of the following situations does the list of numbers involved make an arithmetic progression and why?
(ii) The amount of air present in a cylinder when a vacuum pump removes 1/4 of the air remaining in the cylinder at a time.

Ans: Let’s start from making a sequence of the air amount in the cylinder after every stroke and then check if the sequence makes an AP or not.

Let’s consider the initial amount of air in the cylinder is “X”.

Clearly this becomes our 1st term, \therefore a_1 = X

Next, it is given that the vacuum pump removes \frac{1}{4} of the air present,

hence, air removed by pump in the 1st stroke = \frac{X}{4}

and the balance air in the cylinder will be = X - \frac{X}{4} = \frac{3X}{4}

This becomes our 2nd term, \therefore a_2 = \frac{3X}{4}

Next, air removed by pump in the 2nd stroke = \frac{3X}{4} x \frac{1}{4} = \frac{3X}{16}

and the balance air in the cylinder will be = \frac{3X}{4} - \frac{3X}{16} = \frac{9X}{16}

This becomes our 3rd term, \therefore a_3 = \frac{9X}{16}

Similarly, air removed by pump in the 4th stroke = \frac{9X}{16} x \frac{1}{4} = \frac{9X}{64}

and the balance air in the cylinder will be = \frac{9X}{16} - \frac{9X}{64} = \frac{27X}{64}

This becomes our 4th term, \therefore a_4 = \frac{27X}{64}

Thus, the sequence starts to emerge as X, \frac{3X}{4},  \frac{9X}{16}, \frac{27X}{64},......

Next, let’s check the difference between 2 sets of consecutive terms:

Difference between 1st two terms: a_2 - a_1 = \frac{3X}{4} - X = - \frac{X}{4}

Similarly, difference between next two terms: a_3 - a_2 = \frac{9X}{16} - \frac{3X}{4} = - \frac{3X}{16}

and, difference between next two terms: a_4 - a_3 = \frac{27X}{64} - \frac{9X}{16} = - \frac{9X}{64}

Here, since the difference between any two consecutive terms is not equal, hence the sequence formed is not an AP

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