Q) The vertices of Δ ABC are A (- 2, 4), B(4, 3) and C(1, – 6). Find length of the median BD.

Ans: Let’s plot the points on the graph:

The vertices of Δ ABC are A (- 2, 4), B(4, 3) and C(1, - 6). Find length of the median BD.

Step 1:  To draw median BD, point D lies on AC

Let’s consider the coordinates of D are (X, Y)

Since D is the midpoint of A C, we need to find out the coordinates of D.

We know that the coordinates of mid point of 2 coordinates (X1, Y1) and (X2, Y2) given by:

(X, Y) = (\frac{(X_1 + X_2)}{2}, \frac{(Y_1 + Y_2)}{2})

∴ Value of coordinates of midpoint D of A (- 2, 4) and C (1, – 6) are:

(X, Y) = (\frac{1 + (- 2)}{2}, \frac{(- 6) + 4}{2})

= (\frac{- 1}{2}, - 1)

Step 2: Next, we find length of BD, where B is (4, 3) and D is (\frac{- 1}{2}, - 1)

We know that the distance between two points (X1, Y1) and (X2, Y2) is given by:

S = [(X2 – X1)2 + (Y2 – Y1)2 ]

∴  BD = \sqrt{(\frac{- 1}{2} - 4)^2 + (-1 - 3)^2}

= \sqrt{(\frac{81}{4} + 16)}

= \sqrt{20.25 + 16} =  \sqrt{36.25}

= 6.02

Therefore, the length of the median BD is 6.02 units.

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