Q) Three consecutive integers are such that sum of the square of second and product of other two is 161. Find the three integers.
Ans:
STEP BY STEP SOLUTION
Let’s consider the three consecutive integers as (X – 1), X and (X + 1)
By given condition, X 2 + (X – 1) (X + 1) = 161
∴ X 2 + X 2 – 1 = 161
∴ 2 X 2 = 162
∴ X 2 = 81
∴ X = 9
∴ other two integers are (X – 1) = 9 – 1 = 8 and (X + 1) = 9 + 1 = 10
Therefore, the three consecutive integers are 8, 9 and 10.
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