**Q) Water in a canal, 8 m wide and 6 m deep, is flowing with a speed of 12 km/hour. How much area will it irrigate in one hour, if 0.05 m of standing water is required?**

**Ans: **

**VIDEO SOLUTION**

**STEP BY STEP SOLUTION**

** **Here, it is given that water is flowing out at the rate of 12 km / hour in a canal of size 8m x 6m;

∴ the water flown out in 1 hour = 8 x 6 x 12,000 m^{3}

Now, Since this water will be used for irrigation certain area. It means, the volume of the new area will be equal to the volume of the water flown out in one hour.

∴ A x h = 8 x 6 x 12,000

Here, h, the height of the water = 0.05 m

∴ A x 0.05 = 8 x 6 x 12,000

∴ A = 20 x 8 x 6 x 12,000 = 11,520,000 m^{2 }= 11.52 km^{2}

**Therefore, 11.52 km ^{2} area will be irrigated in one hour.**

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