Q) Mrs. Gupta arranged some snacks for her child’s birthday party. After the guest left she had some food left over. She did not want to waste food and so she contacted a local NGO. She gave 60 pieces of pastries,168 pieces of cookies, and 330 chocolate bars to the team. Now the NGO workers want to make the maximum number of packets with those foods so that no food is left for distributing to the beggars at the roadside. Find the greatest number of packets that they can make.

Ans: Let’s first understand the question.

In this question, some hint words are given. If you read it carefully, you would find how to attempt.

Now, we need to find out “Greatest number of packets” to cater greatest number of beggars.

To achieve this, we need to find HCF so that maximum packets are made.

Let’s find HCF of the 3 numbers:

60 = 2 x 2 × 3 × 5

168 = 2 x 2 x 2 x 3 × 7

330 = 2 × 3 × 5 × 11

HCF = 6

Hence, 6 food items will be kept in 1 packet.

Now, the number of packets required for 60 pieces of pastries = \frac{60}{6} = 10

Similarly, the number of packets required for 168 pieces of cookies = \frac{168}{6} = 28

And the number of packets required for 330 chocolate bars = \frac{330}{6} = 55

∴ Total Packets required = 10 + 28 + 55 = 93

Therefore, total 93 packets required.

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